We continue to develop resources related to the COVID-19 pandemic. See COVID-19 initiatives on Appropedia for more information.

User:Lonny/Erratum Schaums Outlines Thermodynamics for Engineers

From Appropedia
Jump to navigation Jump to search

This is unofficial corrections for answers in Schaum's Outline of Thermodynamics for Engineers. These corrections come from User:Lonny. Please feel free to add correction or critiques of these corrections.

Book Details[edit]

Schaum's Outline of Thermodynamics for Engineers, 2ed (Schaum's Outline Series)
Merle Potter (Author), Ph.D., Craig Somerton (Author)
Publication Date: May 20, 2009 | ISBN-10: 0071611673 | ISBN-13: 978-0071611671 | Edition: 2

Erratum[edit]

1.19e[edit]

Convert [math]\frac{200 ft \cdot lb_f}{sec}[/math] to watts

Givens:
  • [math]\frac{1 ft \cdot lb_f}{sec}=1.356 W[/math]
Book says the answer is 2,712W
Should be: [math]\frac{200 ft \cdot lb_f}{sec}\times\frac{1.356 W \cdot sec}{ft \cdot lb_f}=271.2W[/math]
In addition, with proper significant figures, this should probably be just 271W.

2.20[edit]

A rigid vessel contains water at 400oF. Heat is added so that the water passes through the critical point. Find the quality at 440oF.

Givens:
  • At critical point, [math]v=\frac{0.05053 ft^3}{lb_m}[/math]


  • At 440oF, [math]v_f=\frac{0.019260 ft^3}{lb_m}[/math]


  • At 440oF, [math]v_g=\frac{1.2192 ft^3}{lb_m}[/math]
If it is a rigid vessel the specific volume cannot change. There is only one specific volume at the critical point.
Book says: 0.01728
Should be: <math>x=\frac{v-v_f}{v_g-v_f}=\frac{0.05053 - 0.01926}{1.2192 - 0.01926}=0.02606