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A rigid vessel contains water at 400<sup>o</sup>F. Heat is added so that the water passes through the critical point. Find the quality at 440<sup>o</sup>. | A rigid vessel contains water at 400<sup>o</sup>F. Heat is added so that the water passes through the critical point. Find the quality at 440<sup>o</sup>F. | ||
:Givens: | :Givens: | ||
:*At critical point, <math>v=\frac{0.05053 ft^3}{lb_m}</math> | :*At critical point, <math>v=\frac{0.05053 ft^3}{lb_m}</math> |
Latest revision as of 23:29, 22 August 2017
This is unofficial corrections for answers in Schaum's Outline of Thermodynamics for Engineers. These corrections come from User:Lonny. Please feel free to add correction or critiques of these corrections.
Book Details[edit | edit source]
- Schaum's Outline of Thermodynamics for Engineers, 2ed (Schaum's Outline Series)
- Merle Potter (Author), Ph.D., Craig Somerton (Author)
- Publication Date: May 20, 2009 | ISBN-10: 0071611673 | ISBN-13: 978-0071611671 | Edition: 2
Erratum[edit | edit source]
1.19e[edit | edit source]
Convert to watts
- Givens:
- Book says the answer is 2,712W
- Should be:
- In addition, with proper significant figures, this should probably be just 271W.
2.20[edit | edit source]
A rigid vessel contains water at 400oF. Heat is added so that the water passes through the critical point. Find the quality at 440oF.
- Givens:
- At critical point,
- At 440oF,
- At 440oF,
- If it is a rigid vessel the specific volume cannot change. There is only one specific volume at the critical point.
- Book says: 0.01728
- Should be: <math>x=\frac{v-v_f}{v_g-v_f}=\frac{0.05053 - 0.01926}{1.2192 - 0.01926}=0.02606